120+-46x+3x^2=0

Solution for 120+-46x+3x^2=0 equation:

120+-46x+3x^2=0

We add all the numbers together, and all the variables

3x^2-46x=0

a = 3; b = -46; c = 0;
Δ = b2-4ac
Δ = -462-4·3·0
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-46}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+46}{2*3}=\frac{92}{6}
=15+1/3
$